Building Bricks with Bricks, with Mathematica
2013
In this work we solve a special case of the problem of building an n-dimensional parallelepiped using a given set of n-dimensional parallelepipeds. Consider the identity x^3 = x(x-1)(x-2)+3x(x-1+x). For sufficiently large x, we associate with x^3 a cube with edges of size x, with x(x-1)(x-2) a parallelepiped with edges x, x-1, x-2, with 3x(x-1+x) three parallelepipeds of edges x, x-1, 1, and with x a parallelepiped of edges x, 1, 1. The problem we takle is the actual construction of the cube using the given parallelepipeds. In [DDNP90] it was shown how to solve this specific problem and all similar instances in which a (monic) polynomial is expressed as a linear combination of a persistent basis. That is to say a sequence of polynomials q_0 = 1, and q_k(x) = q_{k-1}(x)(x-r_k) for k > 0. Here, after [Fil10], we deal with a multivariate version of the problem with respect to a basis of polynomials of the same degree (binomial basis). We show that it is possible to build the parallelepiped associated with a multivariate polynomial P(x_1, ..., x_n)=(x_1- s_1)...(x_n-s_n) with integer roots, using the parallelepipeds described by the elements of the basis. We provide an algorithm in Mathematica to solve the problem for each n. Moreover, for n = 2, 3, 4 (in the latter case, only when a projection is possible) we use Mathematica to display a step by step construction of the parallelepiped P(x1,...,x_n).
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